Fixed an error in double parsing logic

src/include/lex.hpp

@@ -20,6 +20,7 @@ struct Token {
     enum TokenType type;
     std::variant<int64_t, double, std::string> value;
 };
+bool operator==(Token const& one, Token const& other);
 std::ostream &operator<<(std::ostream &os, Token const &t);
 
 class Lexer {

src/lex.cpp

@@ -23,6 +23,10 @@ std::ostream &operator<<(std::ostream &os, Token const &t) {
     return os;
 }
 
+bool operator==(Token const& one, Token const& other) {
+    return one.type == other.type && one.value == other.value; 
+}
+
 bool ispunct(char c) {
     for (char i : "!\"#$%&'()*+,-./:;<=>?@[\\]^_`{|}~") {
         if (i == c) return true;
@@ -61,9 +65,10 @@ Token Lexer::lexNumOrSym() {
     // ... this will almost certainly change, won't it?
     string s = acc.str();
     string iterate_over = (s.at(0) == '-') ? s.substr(1) : s;
-    bool is_number = true;
+    bool is_number = false;
     bool dot_seen = false;
-    for (char c : s) {
+    for (char c : iterate_over) {
+        
         if (c == '.') {
             if (dot_seen) {
                 is_number = false;
@@ -72,14 +77,16 @@ Token Lexer::lexNumOrSym() {
             dot_seen = true;
             continue;
         }
-        if (!isdigit(c)) {
+        if (isdigit(c)) {
+            is_number = true;
+        } else {
             is_number = false;
             break;
         }
     }
 
     if (is_number && dot_seen) {
-        if (s == ".")
+        if (iterate_over == ".")
             return {TokenType::Symbol, s};
         return {TokenType::Double, stod(s)};
     } else if (is_number) {